Air Force for Ukrainian cities: How many Patriot batteries need to protect Kharkiv, Dnipro, Odessa, Zaporozhye

According to the most modest estimates, Ukraine requires 7 Patriot batteries, says journalist Denis Popovich. This amount will protect at least 4 largest cities that are constantly under the fire of the enemy are very surprised by these calculations, how many Patriot batteries need to protect Ukrainian cities. And from both official and unofficial sources. Seven batteries, or 25. The battery is at least 2 firing platoons. At least in the set we got. In each platoon of 4 PU, each PU produces 4 rockets.

Accordingly, one battery is 32 rockets. For each ballistic or aerobalistic air target there is a calculation of 2 missilers, since the coefficient of damage to one target by one rocket is approximately 0. 8 (ie 80%).

If you remember that only tonight Kharkiv was released 15 ballistic missiles, then one such battery could theoretically be enough to reflect such an attack, but it all depends on where to put it, because Kharkiv is a big city, which is located close to the border and It would be desirable to protect that Patriot from rocket-artillery strikes from enemy RSLS. We take into account the area of ​​Kharkiv and the fact that the range of damage to the ballistic air target MIM-104 is only 20 km.

Next, we conclude that one such battery for Kharkiv may not be enough. It is advisable at least two. And the same applies to Odessa, Dnipro, Zaporizhzhia. Two batteries at least. Thus, 7 Patriot batteries from 8 PUs will be enough to protect 3-4 large Ukrainian cities. It is possible to treat Dmitry Kuleba, who asked the same number (not 70, not 700, but at least 7), but I take off his hat at least for this attempt. I saw with my own eyes that day in Brussels. This attempt aroused respect.